Differential Pressure: Module 1136_0

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jsmad
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Joined: Wed Feb 11, 2026 4:46 pm

Differential Pressure: Module 1136_0

Post by jsmad »

I am trying to read the pressure from my 1136_0 pressure sensor using the code below (the second line converts the voltage ratio into "inches of H20").

getPressureVoltageRatio = channelPressureSensor.getVoltageRatio()
convertPressureInH2O = (20.073*getPressureVoltageRatio) - 10.037

However, the output gives me a non-zero number when there is no airflow. Is this normal? Do I need to "zero" the reading in the code and is there a native method for doing this or is the best way just to subtract the "zero airflow" output from my above formula?
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burley
Human-Cyborg Relations
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Joined: Tue Sep 27, 2011 2:37 pm
Location: Calgary

Re: Differential Pressure: Module 1136_0

Post by burley »

The sensor has a ±2kPa input range and an output of 0-5Vdc. If the sensor is measuring 0 pressure differential then the output will be 2.5V since that is the middle of the range.
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